y^2+7y+132=0

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Solution for y^2+7y+132=0 equation:


Simplifying
y2 + 7y + 132 = 0

Reorder the terms:
132 + 7y + y2 = 0

Solving
132 + 7y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-132' to each side of the equation.
132 + 7y + -132 + y2 = 0 + -132

Reorder the terms:
132 + -132 + 7y + y2 = 0 + -132

Combine like terms: 132 + -132 = 0
0 + 7y + y2 = 0 + -132
7y + y2 = 0 + -132

Combine like terms: 0 + -132 = -132
7y + y2 = -132

The y term is 7y.  Take half its coefficient (3.5).
Square it (12.25) and add it to both sides.

Add '12.25' to each side of the equation.
7y + 12.25 + y2 = -132 + 12.25

Reorder the terms:
12.25 + 7y + y2 = -132 + 12.25

Combine like terms: -132 + 12.25 = -119.75
12.25 + 7y + y2 = -119.75

Factor a perfect square on the left side:
(y + 3.5)(y + 3.5) = -119.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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